压电谐响应分析求助
一个矩形压电片,如图,Z轴为极化方向。在上下两面上加上位移进行谐响应分析,想提取极化面上的AMPS值却提取不到。不知哪出了问题,求高人指点。命令流如下
/prep7
et,1,5
KEYOPT,1,1,3
KEYOPT,1,3,0
KEYOPT,1,5,0
MP,DENS,1,7750
MP,PERX,1,916
MP,PERY,1,916
MP,PERZ,1,830
TB,PIEZ,1
TBDATA,3,5.4
TBDATA,6,5.4
TBDATA,9,-15.8
TBDATA,14,-12.3
TBDATA,16,-12.3
TB,ANEL,1
TBDATA,1,12.1e10
TBDATA,2,7.54e10
TBDATA,3,7.52e10
TBDATA,7,12.1e10
TBDATA,8,7.52e10
TBDATA,12,11.1e10
TBDATA,16,2.26e10
TBDATA,19,2.11e10
TBDATA,21,2.11e10
BLOCK,-0.0254,0.0254,-0.0127,0.0127,-1e-3,1e-3,
Vatt,1,,1
Esize,0.0005
Vsweep,1
Nsel,s,loc,z,1e-3
Cp,1,volt,all
*GET,N1,NODE,,NUM,MIN
D,all,uz,1e-4
Nsel,s,loc,z,-1e-3
Cp,2,volt,all
*GET,N2,NODE,,NUM,MIN
D,all,uz,-1e-4
Alls
FINISH
/SOL
ANTYPE,3
HARFRQ,0,5000,
NSUBST,50,
KBC,1
SOLVE
FINISH 定义一个面电位为0,可以直接提取另个面电位 hy1966 发表于 2011-9-28 18:07 static/image/common/back.gif
定义一个面电位为0,可以直接提取另个面电位
版主大哥,请问AMPS值在这表示什么呢?是流过提取点的电荷总和,还是电流什么的? 在solid5单元中,是电荷
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