请教关于用虚位移求电磁力矩的问题(有命令流)
/POST1CSYS,1
*CFOPEN,FRAD,DAT
TOR = 0
FRDY = 0
FRDX = 0
BBSUM = 0
*DO,J,3293,3652,1
ESEL,S,,,J
ETABLE,FVWX,NMISC,3
ETABLE,FVWY,NMISC,4
*GET,FXX,ELEM,J,ETAB,FVWX
*GET,FYY,ELEM,J,ETAB,FVWY
*GET,RAD,ELEM,J,CENT,X
*GET,ANG,ELEM,J,CENT,Y
FT=FXX*SIN(ANG)-FYY*COS(ANG)
FRAD=(FYY*SIN(ANG)+FXX*COS(ANG))*0.026
FRDY = FRDY + FYY
FRDX = FRDX + FXX
TOR = TOR +FT*RAD*0.026
*VWRITE,FRAD
(F10.4)
*ENDDO
*VWRITE,TOR, FRDX*0.026,FRDY*0.026
(3F15.9)
*CFCLOS,FRAD,DAT
ALLSEL
FINISH
请教这里乘以0.26的意义是什么 ?为什么还要乘上一个常数 可能是轴向长度，可以共同交流，非常感兴趣，我QQ187291669
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