含永磁铁的电磁场瞬态分析发现涡流分布不对啊
含永磁铁的电磁场2D瞬态分析本想看洛伦兹力分布的，发现洛伦兹力的分布与预期的不对，后来发现是涡流分布不对的原因，再查下去发现在设定时间段内永磁铁的磁感应强度是随时间步长变化的，可我在材料设定是给的是定值矫顽力啊？本以为是加载方式不对，从斜坡加载改成阶跃的还是这个问题，大伙帮忙看看怎么解决啊程序如下：
/TITLE,Lorentz Force
KEYW,MAGNOD,1
/PREP7
ET,1,PLANE53
ET,2,PLANE53,1
A=0.0005 !线圈与工件间距
B=0.0005 !线圈与磁铁间距
L=0.005 !导线间距
W=0.05 !磁铁宽度
G=0.01 !磁铁缝隙
MP,MURX,1,1.15
MP,MGYY,1,7000
MP,MURX,2,1.15
MP,MGYY,2,-7000
MP,MURX,3,1
MP,RSVX,3,1.67E-8
MP,MURX,4,1000
MP,RSVX,4,7E-8
MP,MURX,5,1000
MP,MURX,6,1
RECTNG,0.1,0.3,0,0.01
RECTNG,0.2+G/2,0.2+G/2+0.05,0.011+A+B,0.011+A+B+0.04
RECTNG,0.2-G/2-0.05,0.2-G/2,0.011+A+B,0.011+A+B+0.04
RECTNG,0.2+G/2+0.025-L,0.2+G/2+0.026-L,0.01+A,0.011+A
RECTNG,0.2+G/2+0.025,0.2+G/2+0.026,0.01+A,0.011+A
RECTNG,0.2+G/2+0.025+L,0.2+G/2+0.026+L,0.01+A,0.011+A
RECTNG,0.2-G/2-0.025-L,0.2-G/2-0.026-L,0.01+A,0.011+A
RECTNG,0.2-G/2-0.025,0.2-G/2-0.026,0.01+A,0.011+A
RECTNG,0.2-G/2-0.025+L,0.2-G/2-0.026+L,0.01+A,0.011+A
RECTNG,0.2-G/2-0.05,0.2+G/2+0.05,0.011+A+B+0.04,0.011+A+B+0.05
PCIRC,0.6, ,-90,90,
AOVLAP, ALL
NUMCMP,AREA
APLOT
ASEL,S,AREA,,1
AATT,4,1,1,0 !AATT,MAT,REAL,TYPE,ESYS,SECN
ASEL,S,AREA,,2
AATT,1,1,1,0
ASEL,S,AREA,,3
AATT,2,1,1,0
ASEL,S,AREA,,4,9,1
AATT,3,1,2,0
ASEL,S,AREA,,10
AATT,5,1,1,0
ASEL,S,AREA,,11
AATT,6,1,1,0
ASEL,ALL
APLOT
SAVE
ESIZE,0.001
MSHAPE,0,2D
MSHKEY,1
AMESH,1,9,1
ESIZE,0.001
MSHAPE,0,2D
MSHKEY,0
AMESH,10
ESIZE,0,0
MSHKEY,0
SMRTSIZE,2
AMESH,11
NSEL,ALL
FINISH
NPLOT
/SOLU
ANTYPE,4
TRNOPT,FULL
NSEL,S,EXT
D,ALL,AZ,0
SAVE
ESEL,ALL
ESEL,S,MAT,,3
NSLE,S
NO1=NODE(0.2-G/2-0.025-L,0.01+A,0)
NSEL,R,LOC,X,0.2-G/2-0.025-L,0.2-G/2-0.026-L
NSEL,R,LOC,Y,0.01+A,0.011+A
CP,1,VOLT,ALL
ESEL,S,MAT,,3
NSLE,S
NO2=NODE(0.2-G/2-0.025,0.01+A,0)
NSEL,R,LOC,X,0.2-G/2-0.025,0.2-G/2-0.026
NSEL,R,LOC,Y,0.01+A,0.011+A
CP,2,VOLT,ALL
ESEL,S,MAT,,3
NSLE,S
NO3=NODE(0.2-G/2-0.025+L,0.01+A,0)
NSEL,R,LOC,X,0.2-G/2-0.025+L,0.2-G/2-0.026+L
NSEL,R,LOC,Y,0.01+A,0.011+A
CP,3,VOLT,ALL
ESEL,S,MAT,,3
NSLE,S
NO4=NODE(0.2+G/2+0.025-L,0.01+A,0)
NSEL,R,LOC,X,0.2+G/2+0.025-L,0.2+G/2+0.026-L
NSEL,R,LOC,Y,0.01+A,0.011+A
CP,4,VOLT,ALL
ESEL,S,MAT,,3
NSLE,S
NO5=NODE(0.2+G/2+0.025,0.01+A,0)
NSEL,R,LOC,X,0.2+G/2+0.025,0.2+G/2+0.026
NSEL,R,LOC,Y,0.01+A,0.011+A
CP,5,VOLT,ALL
ESEL,S,MAT,,3
NSLE,S
NO6=NODE(0.2+G/2+0.025+L,0.01+A,0)
NSEL,R,LOC,X,0.2+G/2+0.025+L,0.2+G/2+0.026+L
NSEL,R,LOC,Y,0.01+A,0.011+A
CP,6,VOLT,ALL
ALLSEL,ALL
NSEL,ALL
EPLOT
SAVE
T=1E-6
C=0
N=40
PI=2*ASIN(1)
CON=1E-3/N
NEQIT,10
*CREATE,LOAD
TIME,T
DELTIM,1E-6, , ,1
KBC,1
I=SIN(2*PI*1E3*T)
*IF,C,LE,N-1,THEN
F,NO1,AMPS,I
F,NO2,AMPS,I
F,NO3,AMPS,I
F,NO4,AMPS,-I
F,NO5,AMPS,-I
F,NO5,AMPS,-I
*ELSE
F,NO1,AMPS,0
F,NO2,AMPS,0
F,NO3,AMPS,0
F,NO4,AMPS,0
F,NO5,AMPS,0
F,NO5,AMPS,0
*ENDIF
T=T+CON
C=C+1
OUTRES,ALL,ALL,
ESEL,ALL
EPLOT
SOLVE
*END
*DO,P,1,81
*USE,LOAD
*ENDDO
FINISH
/POST26
后处理部分就是看看每个单元上JT的分布，程序未写出 这个程序有点繁琐，大家可以改成一步加载试试，也会有永磁铁的磁感应强度发生变化导致涡流产生 怎么没有人应助啊？？？ YY的，这个问题俺已经自己攻破，先进行静态分析再瞬态分析就OK了 请问过去的问题是什么呢？为什么先进行静态分析再瞬态分析就OK了？ shagf 发表于 2011-7-4 15:00 static/image/common/back.gif
YY的，这个问题俺已经自己攻破，先进行静态分析再瞬态分析就OK了
嗯，先静态，再瞬态分析，不知道是什么道理，楼主可否写详细点呢？以便于后来者也学习一下 回复楼上二位，具体就是先关闭时间步积分进行一下solve，然后打开积分时间步Solve 谐波分析的话，不能加永磁体的说 谢谢楼主。请问在这个过程中能否考虑速度效应呢？比如说我现在需要模拟铝板在两块永磁体之间运动所属道德力，纳闷我这个可否采用瞬态分析呢？谢谢。 时间积分效应
这些载荷步选项用以确定在分析中是否包括瞬态效应，例如涡流阻尼效应和电感。
注意：对于瞬态分析，ANSYS假设时间积分效应是打开的（除非由于建立初始条件而将其关闭）。如果时间积分效应被关闭，则ANSYS相当于是计算静态解。
开关时间积分效应的方式如下：
命令：TIMINT
GUI：Main Menu>Solution>-Load Step Opts-Time/Frequenc>Time Integration 我的也是这个问题！ shagf 发表于 2011-7-4 15:00 static/image/common/back.gif
YY的，这个问题俺已经自己攻破，先进行静态分析再瞬态分析就OK了
能不能把你的模型 及 分析结果 分享一下 如果想验证的话，请按照原发代码执行一遍；关闭时间积分执行一段时间后，再打开时间积分，两次的结果明显不同 0603yuanqian 发表于 2011-10-19 22:45 static/image/common/back.gif
谐波分析的话，不能加永磁体的说
谐波分析肯定不能加永磁铁，但是考虑到永磁铁时必须用瞬态分析，对吧？
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