电磁场培训手册中有个“2D变压器应用实例”,谐波分析。
问题描述:
1)变压器初级构成:2欧直流电阻,1080匝
2)变压器次级构成:0.02欧直流电阻,108匝
3)电压源:60V峰值,60Hz
4)线圈在75C
5)叠层长度:70mm
分析过程:
1)利用对称性
2)模拟次极短路情况
3)建立电路模型:实常数设置、耦合
4)进行交流分析
5)后处理:电流、功率
ansys仿真图见图1
结果:
电流:初极线圈:-0.809+j3.39(幅值为3.485)
次极线圈:8.09-j33.87
我对上述实例进行两种尝试,所遇问题如下:
尝试一:由于我以后的模型会涉及到瞬态分析,所以我对上述实例的命令流进行修改,得到下面瞬态分析命令流:
!1/2截面,外接直流电阻,瞬态分析
/prep7
/title, two-winding transformer
et,1,53
et,2,53,3
mp,murx,1,1
mp,murx,2,10000
mp,murx,3,1
mp,rsvx,3,1e-12
rectng,1,6,.75,3.25
rectng,1,6,3.75,6.25
rectng,1,6,3.25,3.75
aglue,all
rectng,0,7,0,7
aovlap,all
asel,s,area,,1 ! primary
aatt,3,1,2
asel,s,area,,2 ! secondary
aatt,3,2,2
asel,s,area,,5 ! iron
aatt,2,3,1
asel,s,area,,4 ! window
aatt,1,3,1
asel,all
esize,.5
amesh,all
asel,,real,,1
asum
*get,acond,area,,area
acond=acond/1e4
alls
csys
arscal,all,0,0,.01,.01,,,,1
*SET,c_fac,.653184
r,1,acond,360*3,0.07,1,c_fac
r,2,acond,36*3,0.07,1,c_fac
wpstyl,0.01
muz=12.57e-7
T=1E-8
PI=2*ASIN(1)
f=60
um=60
u=um*SIN(2*PI*f*T)
con=0.002
c=0
R,3,u, ,
*GET,_zz2,active,,csys
*GET,_zz3,active,,dsys
CSYS,0
DSYS,0
N,664,0.12,-0.3E-01,0
N,665,0.12,-0.12,0
CSYS,_zz2
DSYS,_zz3
RMOD,3,15,0.4E-01,1
ET,3,CIRCU124,4,0
TYPE,3
REAL,3
MAT,1
N,666,0.16,-0.75E-01,0 E,664,665,666
R,4,1,
*GET,_zz2,active,,csys
*GET,_zz3,active,,dsys
CSYS,0
DSYS,0
n,667,0.12,-0.08,0
CSYS,_zz2
DSYS,_zz3
RMOD,4,15,0,1
ET,4,CIRCU124,5,0
TYPE,4
REAL,4
MAT,1
E,664,667,122
r,5,2,
*GET,_zz2,active,,csys
*GET,_zz3,active,,dsys
CSYS,0
DSYS,0
CSYS,_zz2
DSYS,_zz3
RMOD,5,15,0,1
ET,5,CIRCU124,0,0
TYPE,5
REAL,5
MAT,1
E,667,665
R,6,1e-008,
!r,6,1e8
*GET,_zz2,active,,csys
*GET,_zz3,active,,dsys
CSYS,0
DSYS,0
N,668,0.13,0.16,0
N,669,0.13,0.8E-01,0
CSYS,_zz2
DSYS,_zz3
RMOD,6,15,0.3E-01,1
ET,6,CIRCU124,0,0
TYPE,6
REAL,6
MAT,1
E,668,669
R,7,1,
*GET,_zz2,active,,csys
*GET,_zz3,active,,dsys
CSYS,0
DSYS,0
n,670,0.13,0.12,0
CSYS,_zz2
DSYS,_zz3
RMOD,7,15,0,1
ET,7,CIRCU124,5,0
TYPE,7
REAL,7
MAT,1
E,668,670,314
r,8,0.02
*GET,_zz2,active,,csys
*GET,_zz3,active,,dsys
CSYS,0
DSYS,0
CSYS,_zz2
DSYS,_zz3
RMOD,8,15,0,1
ET,8,CIRCU124,0,0
TYPE,8
REAL,8
MAT,1
E,670,669
FLST,5,2,1,ORDE,2
FITEM,5,665
FITEM,5,669
NSEL,R, , ,P51X
d,all,volt
esel,,ename,,53
esel,r,real,,1
nsle
cp,1,curr,all
cp,2,emf,all
esel,,ename,,53
esel,r,real,,2
nsle
cp,3,curr,all
cp,4,emf,all
alls
esel,,ename,,53
nsle
nsel,r,ext
d,all,az
alls
FINISH
/sol
ANTYPE,4
TRNOPT,FULL
time,t
kbc,0 !ramp
nsubst,5 !substeps
neqit,10
c=c+1
outres,all,last
OUTPR,ALL,ALL
alls
solve
fini
*do,c,1,89
transformer
*enddo
transformer.mac: /prep7
t=t+con
u=um*SIN(2*PI*f*T)
r,3,u
fini /sol
ANTYPE,,REST
time,t
kbc,0 !ramp
nsubst,5 !substeps
neqit,10
c=c+1
outres,all,last
OUTPR,ALL,ALL
alls
solve
fini
查看线圈电流随时间变化曲线,如图2所示,电流稳态时,幅值为3.485A,与前面谐波分析时的线圈电流幅值吻合。
查看铁心一次侧某一单元的磁感应强度x分量Bx,如图3所示
问题:为什么Bx随时间变化曲线会相对于x轴有一直流偏置?从理论分析上来看,变压器二次侧短路时,一次侧磁通正比于外加电压,而磁密正比于磁通,难道不应该是关于x轴对称的正弦量吗?不知是我建模的问题还是ansys计算的问题? 尝试二:实例中采取的是对称建模,我现将模型补完整,谐波分析。ansys仿真如图4,命令流如下:
!完整截面,外接直流电阻,谐波分析
/prep7
/title, two-winding transformer
et,1,53
et,2,53,3
mp,murx,1,1
mp,murx,2,10000
mp,murx,3,1
mp,rsvx,3,1e-12
rectng,1,6,.75,3.25
rectng,1,6,3.75,6.25
rectng,1,6,3.25,3.75
aglue,all
rectng,8,13,.75,3.25
rectng,8,13,3.75,6.25
rectng,8,13,3.25,3.75
aglue,all
rectng,0,14,0,7
aovlap,all asel,s,area,,1 ! primary
aatt,3,1,2
asel,s,area,,3
aatt,3,9,2
asel,s,area,,2 ! secondary
aatt,3,2,2
asel,s,area,,5
aatt,3,10,2
asel,s,area,,8 ! iron
aatt,2,5,1
asel,s,area,,4 ! window
aatt,1,5,1
asel,s,area,,7
aatt,1,5,1
asel,all
esize,.5
amesh,all
asel,,real,,1
asum
*get,acond,area,,area
acond=acond/1e4
alls
csys
arscal,all,0,0,.01,.01,,,,1
*SET,c_fac,.653184
r,1,acond,360*3,0.07,1,c_fac
r,2,acond,36*3,0.07,1,c_fac
r,9,acond,360*3,0.07,-1,c_fac
r,10,acond,36*3,0.07,-1,c_fac
wpstyl,0.01
R,3,60, ,
*GET,_zz2,active,,csys
*GET,_zz3,active,,dsys
CSYS,0
DSYS,0
N,1223,0.22,-0.3E-01,0
N,1224,0.22,-0.12,0
CSYS,_zz2
DSYS,_zz3
RMOD,3,15,0.4E-01,1
ET,3,CIRCU124,4,0
TYPE,3
REAL,3
MAT,1
N,1225,0.26,-0.75E-01,0
E,1223,1224,1225
R,4,1,
*GET,_zz2,active,,csys
*GET,_zz3,active,,dsys
CSYS,0
DSYS,0
n,1226,0.22,-0.06,0
CSYS,_zz2
DSYS,_zz3
RMOD,4,15,0,1
ET,4,CIRCU124,5,0
TYPE,4
REAL,4
MAT,1
E,1223,1226,122
R,5,1,
*GET,_zz2,active,,csys
*GET,_zz3,active,,dsys
CSYS,0
DSYS,0
n,1227,0.22,-0.09,0
CSYS,_zz2
DSYS,_zz3
RMOD,5,15,0,1
ET,5,CIRCU124,5,0
TYPE,5
REAL,5
MAT,1
E,1226,1227,471
r,11,2
*GET,_zz2,active,,csys
*GET,_zz3,active,,dsys
CSYS,0
DSYS,0
CSYS,_zz2
DSYS,_zz3
RMOD,11,15,0,1
ET,9,CIRCU124,0,0
TYPE,9
REAL,11
MAT,1
E,1227,1224
R,6,1e-008,
*GET,_zz2,active,,csys
*GET,_zz3,active,,dsys
CSYS,0
DSYS,0
N,1228,0.23,0.16,0
N,1229,0.23,0.7E-01,0
CSYS,_zz2
DSYS,_zz3
RMOD,6,15,0.3E-01,1
ET,6,CIRCU124,0,0
TYPE,6
REAL,6
MAT,1
E,1228,1229
R,7,1,
*GET,_zz2,active,,csys
*GET,_zz3,active,,dsys
CSYS,0
DSYS,0
n,1230,0.23,0.13,0
CSYS,_zz2
DSYS,_zz3
RMOD,7,15,0,1
ET,7,CIRCU124,5,0
TYPE,7
REAL,7
MAT,1
E,1228,1230,290
R,8,1,
*GET,_zz2,active,,csys
*GET,_zz3,active,,dsys
CSYS,0
DSYS,0
n,1231,0.23,0.10,0
CSYS,_zz2
DSYS,_zz3
RMOD,8,15,0,1
ET,8,CIRCU124,5,0
TYPE,8
REAL,8
MAT,1
E,1230,1231,650
r,12,0.02
*GET,_zz2,active,,csys
*GET,_zz3,active,,dsys
CSYS,0
DSYS,0
CSYS,_zz2
DSYS,_zz3
RMOD,12,15,0,1
ET,10,CIRCU124,0,0
TYPE,10
REAL,12
MAT,1
E,1231,1229
FLST,2,2,1,ORDE,2
FITEM,2,1224
FITEM,2,1229
D,P51X,VOLT,0
esel,,ename,,53
esel,r,real,,1
nsle
cp,1,curr,all
cp,2,emf,all
esel,,ename,,53
esel,r,real,,2
nsle
cp,3,curr,all
cp,4,emf,all
esel,,ename,,53
esel,r,real,,9
nsle
cp,5,curr,all
cp,6,emf,all
esel,,ename,,53
esel,r,real,,10
nsle
cp,7,curr,all
cp,8,emf,all alls
esel,,ename,,53
nsle
nsel,r,ext
d,all,az
alls FINISH
/sol
antype,harm
harfrq,60
alls
solve
fini
结果:
电流:初极线圈:-0.21078+j1.7660(幅值为1.779A)
问题:建完整截面模型所得到的电流实部、虚部值为什么和1/2截面模型所得到的电流实部、虚部值不一样?
困扰很久了,因为后面所要建的模型会基于2D变压器,所以把这个例子好好的折腾了一番,希望大家帮帮忙。
[ 本帖最后由 北极熊甲 于 2007-12-28 18:42 编辑 ] |